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Construction Of Blended Algebraic Surface With High Geometric Continuity

Posted on:2007-04-06Degree:MasterType:Thesis
Country:ChinaCandidate:S W YunFull Text:PDF
GTID:2120360182996216Subject:Applied Mathematics
Abstract/Summary:PDF Full Text Request
One of the central questions in CAGD is blending of surfaces. Recently,many results in commutative algebra and algebraic geometry can be calculatedbecause of the work of Groebner and Wu, which in turn helped the research ofimplicit algebraic surfaces. In this article, we will study the blending of implicitalgebraic surfaces with the intersections on planes by using algebraic geometry.First, we consider G2 blending of two quadratic surfaces.Hypothesis: Let g1 and g2 be irreducible quadratic polynomials, whichdetermine two distinct surfaces, and let h1 and h2 be linear function, whichdetermine two different planes. Assume that S(gβ) and S(hβ) intersecttransversely with an irreducible quadratic intersection (β=1,2).Under this hypothesis, we let polynomial f of degree 4 such thatf=u1g1+a1g2+a2h23 (1)Anduβ = uβ1h12+uβ2h22+uβ0h1h2 β =1,2 ( 2 )Where uβ1, uβ2,uβ0≠0 and a1 ,a2 are linear functions. We have thefollowing:Theorem 1 Let S ( h1 )≠ S(h2), if (1)is tenable,and u1 ,u2are held by(2),then there exists λ ≠0 and linear functions b1 ,b2, c1 ,c2,such thatg1 + b1h1=λ g2+b2h2, (3)(u11h1+ u10h2)g1+c1h12=(u21h1+u20h2)g2+c2h22 ( 4 )Theorem 2 Let S ( h1 )≠ S(h2). Suppose that there exists quadraticpolynomial g, such thatg = g1 +b1h1=λ g2+b2h2 (5)If there exists real numbers μ , ω∈ R ,μω≠0, such that b1 ,b2 satisfy thefollowing constraint:h 2 + μh 1=ω(b 1+μb2), ( 6 )Then there exists polynomial f of degree 4 as following, such that the surface S(f)and S(gβ) meet with G2 continuity along the curve S(gβ, hβ)f = ug?vh1h2 (7)whereu = ω ( μ2 h12+h22?μh1h2) ( 8 )v = μ 2 h12?ω( μh1?h2)b1=h22?μω(h2?μh1)b2 ( 9 )Theorem 3 Suppose S ( h1 )∩ S(h2)≠φ, there exists polynomial f of degree4 as (1), and u1 ,u2are hold by(2), such that the surface S(f) and S(gβ) meet withG2 continuity along the curve S(gβ, hβ) if and only if there exists real numbersλ ≠ 0, μ≠0 and??????+===000211202100100λλλλλλμμμgggggg( 1 0 )Where g iλj are the expansion coefficients of g 1 ? λg2 in terms of h1 ,h2.Moreover, S(f) is defined by (7),(8),(9).Theorem 4 Suppose S ( h1 )∩ S(h2)=φ and denote h 2 = h1+δ, there existspolynomial f of degree 4 as (1), and u1 ,u2are hold by(2), such that the surfaceS(f) and S(gβ) meet with G2 continuity along the curve S(gβ, hβ) if and only ifthere exists real numbers λ ≠ 0, μ≠0 and??????+++=+=+=(1)(1)0(1)()02212010λλλλλλδδμμμδγggggggt(11)Where t ∈ Span( N(

))is a linear polynomial, γ is a constant, and g iλare the expansion coefficients of g 1 ? λg2 in term of h1 . Moreover, S(f) isdefined by (7),(8),(9).We also give specifically express the condition of the blending of quadraticsurfaces, and discuss some examples.Next, we extend the Division Algorithm, and use it to obtain a generalmethod to determine the possibility of Gk blending.Hypothesis: Let gβ be irreducible polynomials with degree mβ respectively,which determine two distinct surfaces, and let hβ be linear functions. Assumethat S(gβ) and S(hβ) intersect transversely with an irreducible intersections ofdegree mβ respectively (β=1,2,3).Under this hypothesis, we give corresponding proposition on everyconstitution of S(h1) , S(h2) and S(h3). Please vide proposition 3.1 toproposition 3.8 in this paper.These propositions reduce the previously developed symbol computationfor Gk blending to a very simple linear system according to different situations,which can be implemented easily in practice.

Keywords/Search Tags:Construction
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