Study Of χ_cJâ†'K~*(892)~0K~*(892)~0

In1979, BNL(Brookhaven National Laboratory) and SLAC(Stanford Linear Acceler-ator) had found the J/ψ almost at the same time. The particles of ψ{2S),ψ(3770) and so on were subsequently discovered. The series of discoveries confirmed that most of the resonances are composed of a quark and an antiquark. The Beijing Electron Positron Col-lider (BEPC) consist of the injector, the storage ring, the transportation line. The storage ring is a sports track shaped accelerator with a circumference of240.4m. the transporta-tion line is200m long. The BEPC can operate at√s=4GeV. It is a good place where we can study the charmonium physics.In the Standard Model, XcJ is the P wave triple state3Pj of the charmonium family. Studies on XcJ decays designed as for understanding the helicity selection rule. Accord-ing to the helicity selection rule, Xcl decays to double vector meson has small branching ratio. If the final states are the identical particles or the approximate identical particles, for example χc1â†'φφ,ωω,the allowed orbital angular momentum is only2(L=2)and the branching ratio gets smaller in theory. But the BESâ…¢ measurements show that the branching ratios of χc1â†'φφ,ωω,are lager than expected in theory.Experimentally, XcJ can be accesible from the transiton ψ(2S)â†'γχcJ and these XcJ data sample have a lower hadronic background compared with Hadron Collider(such as pp collider). As a result, the ψ(2S) data is regarded as an ideal laboratory to study XcJ decays and physical properties of XcJ.Presently, our knowledge on the triplet of P-wave states is less than that for the J/ψ and ψ(2S), and the observed hadronic decays of XcJ state accounts for15%of total decay width. The study of XcJ decays in experiment is helpful for us to understand its, property and decay mechanisms.In this paper, based on large ψ(2S) data sample collected at BESâ…¢, we have obe-served the significant signals from XcJâ†'K*(892)0K*(892)0, XcJâ†'K*(S92)0K-Ï€+c.c. The numerical results are listed below:·Br(χc0â†'K*(892)0K*(892)0)=(1.0±0.06±0.081)×10-3·Br(χc0â†'K*(892)0K*-Ï€+)=(3.8±0.09±0.30)×10-3·Br(χc0â†'K*(892)0K*-Ï€-)=(3.9±0.1±0.31)×10-3·Br(χc0â†'K*(892)0K*(892)0)=(?)=0.05±0.072)×10-8 ·Br(χc0â†'K*(892)0K-Ï€+)=(1.7±0.13±0.13)×10-3·Br(χc0â†'K*(892)0K+Ï€-)=(1.9±0.05±0.15)×10-3·Br(χc0â†'K*(892)0K*(892)0)=(3.0±0.08±0.24)×10-3·Br(χc0â†'K*(892)0K-Ï€+)=(2.4±0.07±0.19)×10-3·Br(χc0â†'K*(892)0K+Ï€-)=(2.5±0.07±0.20)×10-3...