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The Study On Superconducting Properties And First-principles Calculation Of Rare-earth Doped Eu0.5Ln0.5BiS2F

Posted on:2023-09-11Degree:MasterType:Thesis
Country:ChinaCandidate:B LinFull Text:PDF
GTID:2530306845954419Subject:Condensed matter physics
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Superconductivity is a hot topic in condensed matter physics.For more than 100 years since the discovery of superconductivity,researchers have been searching for new superconductors.The new family of the BiS2-based superconductors was discovered couple of years ago.As the Cu-based and Fe-based superconductors,the BiS2-based superconductors are layered structure.In the BiS2-based superconductor family,the parent compounds are usually insulators,such as La BiS2O and Sr BiS2F.However,Eu BiS2F exhibits different metallic behavior under normal state due to the self-doping effect,which is caused by hybridization of Eu 4f and Bi 6p orbitals.Thus,superconductivity can be achieved without doping.Below 280 K,ρ(T)curve shows a hump which is caused by the possible charge density wave.The superconducting transition temperature TC of Eu BiS2F is only 0.3 K.The low TC of Eu BiS2F may be caused by three reasons:(i)the charge density wave;(ii)the Pairing breaking caused by the Eu magnetic moment;(iii)the low electron doing level(x~0.2).The doping can introduce carriers and suppress charge density wave,so doping at the Eu position of Eu BiS2F is a rational route to improve TC.The structure,resistivity,susceptibility and specific heat of Eu0.5Ln0.5BiS2F(Ln=La,Ce,Pr,Nd,Sm)were studied in this paper.And the electron structure was calculated by first principles calculation.The main results of the thesis are as follows:1.Eu0.5Ln0.5BiS2F polycrystalline samples were successfully synthesized.The TC of Eu0.5La0.5BiS2F was 2.82 K,which is 9 times that of the parent compound.After doping,no hump was observed in theρ(T)curve.It means that the charge density wave was suppressed.Theρ(T)curve of Eu0.5Ln0.5BiS2F shows semiconducting-like behavior with negative coefficient of resistivity.The effective magnetic moment(7.96μB)of Eu in Eu0.5La0.5BiS2F sample is calculated by means of curie-weiss law,which is in good agreement with the theoretical value of Eu2+.After deducting the electron and phonon contribution,the magnetic specific heat shows a relatively rounded peak at 1.3 K,and the parent compound also shows the same behavior at 1.6 K,which could be attributed to the spin glass transition.By integrating the magnetic specific heat,we got the magnetic entropy(9 J·K-1·mol-1),which is 50%of the theoretical magnetic entropy of Eu2+.According to this,we got the conclusion that the valence states of Eu are basically divalent.2.We optimized the lattice structures of Eu BiS2F with different magnetic orders and Eu0.5La0.5BiS2F with different doping sites through the first-principles calculation.After comparing the free energy of different models,the ground state is determined.And the electron structure of the ground state is calculated.Before doping,the localized Eu 4f orbitals cross the fermi energy level.Thus,Eu 4f orbitals have filled and empty states.The filled states represent Eu2+,and the empty states represent Eu3+.The Eu 4f orbitals hybridize with Bi 6p orbitals,and donate electrons to Bi 6p orbitals.So,the conduction band of Eu BiS2F is filled with the transferred electrons.It is the reason why Eu BiS2F behaves like metal in normal state and induces SC without doping.After doping,Eu 4f orbitals don’t cross the fermi energy level,and don’t hybridize with Bi 6p orbitals.Therefore,we believe that the Eu is all divalent.The induced electrons is all comes from La.
Keywords/Search Tags:BiS2-based superconductor, Charge density wave, First principles calculation, Orbitals hybridization
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