Preparation Of CaAlBo₄:M(M=Eu³⁺,Cr³⁺,Dy³⁺) Fluorescent Material And Study On Its Spectral Characteristics

Nowadays,in the era of high-tech information technology,new lighting sources have replaced the role of traditional fossil energy.New lighting sources W-LEDs have already shined in the market.W-LEDs rely on their green energy saving,high brightness,high efficiency,and high stability.And easy production and other advantages have become the leader in luminescent materials.In order to urgently need better luminous performance,a wider range of color temperature and stable color diversity,it is very necessary to develop a series of phosphors with stable and efficient light intensity.Among many chemical systems,boroaluminate-doped rare-earth materials are currently an important research direction for new energy sources,and the synthetic materials of the boroaluminate system are easy to store in the air,and the production process is relatively simple.In addition,studies have shown that,compared with rare earth elements,transition metal element chromium as an activator has also become an important member of the luminescent materials due to its lower cost and the particularity of its own electronic layer structure.In this paper,three different element-doped boroaluminate substrates are selected to synthesize fluorescent materials,and their luminescence properties are studied by analyzing the data.The main contents are as follows:1.Using CaCO₃(AR),Al₂O₃(AR),H₃BO₃(AR)as host materials,Eu₂O₃as activator,Eu³⁺doped CaAlBO₄red fluorescent material was prepared for the first time,and the samples were measured in steady state by fluorescence spectrometer.XRD showed that the doping of Eu³⁺ions did not affect the crystalline phase of the CaAlBO₄matrix.The experimental results show that the excitation peaks are mainly composed of ⁷F₀?⁵D₄,⁷F₀?⁵G₄,⁷F₀?⁵L₀,⁷F₀?⁵D₃,⁷F₀?⁵D₂,⁷F₀?⁵D₁at 365nm,374nm,383nm,396nm,413nm,468nm.The emission peaks are mainly composed of⁵D₀?⁷F₀,⁵D₀?⁷F₁,⁵D₀?⁷F₂,⁵D₀?⁷F₃electronic transitions at 617nm,623nm,628nm,and 649nm.The main emission peak of CaAlBO₄:x Eu³⁺sample is located at622nm.At the same time,the amount of Eu³⁺ion doping has a certain influence on the inside of the CaAlBO₄matrix lattice.It is concluded that CaAlBO₄:x Eu³⁺finally exhibits red emission under ultraviolet excitation,and the optimal doping amount of rare earth ion Eu³⁺x=1%is determined.2.The transition metal Cr³⁺is used as the activator,the orthorhombic structure CaAlBO₄is used as the matrix material,and the high temperature solid phase method is used to synthesize the CaAlBO₄:x Cr³⁺fluorescent material.The size of Cr³⁺is similar to the Al³⁺radius in the matrix,so the Cr³⁺ions successfully enter the matrix CaAlBO₄lattice Instead of Al³⁺ions,XRD has no impurity phases.The excitation belt consists of two wide peaks 350 to 460nm and 480 to 630nm,and the light intensity of the 480 to 630nm excited band is significantly higher than the light intensity of the excitation belt of 350 to 460nm.The excitation of 350?460nm attributed to ⁴A_2g(F)?⁴T_1g(F)transition at 414nm at Cr³⁺ion 480 to 630nm attributed to ⁴A_2g(F)?⁴T_2g(F)transition at Cr³⁺ion 556nm.For CaAlBO₄:xCr³⁺red phosphor luminous properties,such as ion-doped concentration,temperature and time,and H₃BO₃dosage,etc.,and perform multiple experiments to finally derive the doping amount of Cr³⁺ions.CaAlBO₄There is a certain effect inside the matrix lattice,and the optimum doping amount x=2%of CaAlBO₄:x Cr³⁺is determined.3.Research on the spectral characteristics of the synthesized CaAlBO₄:x Dy³⁺fluorescent material.At a monitoring wavelength of 576nm,the excitation spectrum ranges from ultraviolet to blue light.The excitation spectrum ranges from ultraviolet to blue region.The experimental results show that the excitation peaks are mainly293nm?323nm?349nm?364nm?384nm?425nm?452nm?472nm at ⁶H_15/2?⁴L_3/2?6H15/2?⁴L19/2?6H15/2?⁶P7/2?6H15/2?⁶P5/2?6H15/2?⁴I13/2?6H15/2?⁴G11/2?6H15/2?⁴I15/2?⁶H_15/2?⁴F_9/2electronic transition composition.The strongest excitation peak of CaAlBO₄:x Dy³⁺sample is located at 349nm,and the strongest emission peak is located at 576nm.At the same time,the amount of Dy³⁺ion doping has a certain effect on the spectral luminescence performance of the CaAlBO₄matrix.It is concluded that CaAlBO₄:x Dy³⁺finally exhibits yellow light emission under ultraviolet excitation,and the optimal doping amount of rare earth ion Dy³⁺x=2%is determined.