In this paper, we mainly discuss how to solve a new type of inverse eigenvalue problem of periodic Jacobi Matrix. If we write the periodic Jacobi matrix (?)n as:A new inverse eigenvalue problem has put forward as follows: Given the data:λ= {λ1≤λ2≤...≤λn} , v= {v1 < v2 < ... < vn} andβ> 0, how do we construct a periodic Jacobi matrix (?)n, which must satisfies the following conditions:By permuting the rows and columns of Jn, we may got a new matrix Jn*Calculating its eigenpolynomial, we get: We substitute vk forλin this equation; however, due to the overlap betweenλand v, there are two kinds of situations:1. if vk andγi, do not have double root, we substitute vk forλdirectly.2. if vk andγi, do have double root, we calculate the limit of both sides asλapproaches tovk.Both of these two situations will derive to a non-linear equation set, which may be solved by Newton iterative method. After getting the numerical solutions, we may calculate the values ofα1,αn,β1,βn-1. What's more, by applying Lanczos method, we may get the values of elements in J2,(n-1) Thus, we construct the periodic Jacobi matrix (?)n .
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