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From Discrete Homoclinic To Continuous Homoclinic

Posted on:2008-12-07Degree:MasterType:Thesis
Country:ChinaCandidate:W B WangFull Text:PDF
GTID:2120360212495758Subject:Computational Mathematics
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we will consider a parameterized dynamical systemand it's one-step method:where e is the step size.(H1) are fixed points of has no eigenvalue on the unit circle. By k±s,u we denote the numbers of stable eigenvalue and unstable eigenvalue of then there existsδ> 0, for |λ-λ|-|<δwe have(H2)At A = A, the one-step method xn+1 =ψ(xn,λ,ε) possesses a transversal connecting orbit (x|-)Z = ((x|-)n)n∈Z which satisfiesIn case of x|-+ = x|--, such an orbit is called homoclinic orbit, otherwise it is called hctcrclinic orbit.In this paper, we only discuss the case of homoclinic orbit. According to bibliography [23], we can obtain the following property.Corollary 1.1. Assume (H1)-(H2), forε> 0, there exists interval (λ0-(ε),λ0+(ε)), such that for anyλ∈(λ0-(ε),λ0+(ε)), the map (2.2) possesses a transversal homoclinic orbit (x|-z(λ),λ), and satisfies x|-Z(λ|-) = x|-z, whenλ=λ0±(ε), the map (2.2) has a one-tangential homoclinic orbit respectively. See figurel we define the operatorΓ| as follows:and thenand the corresponding variational equation:Now we have the following conclusion.Theorem 1.1. Assume (H1) - (H2). Then for 0 <ε<ε1, for anyλ|-∈(λ0- (ε),λ0+(ε)), x|-Zare ragular solutions of the equationΓ|·,λ|,ε = 0, i.e.Γ|<sub>xZ(x|<sub>Z,λ|,ε) are homeomorphisms.n=+oo(H3) Assume , where are theunique solution of the equationThen we also define the operator:With this and the operatorΓ|, we can define the operator F|:The following theorem contains the main properties of the operator F|. Theorem 1.2. Assume (H1) - (H3). Then there existsε1 > 0, such that 0 <ε<ε1,for anyare regular solutions of the equation F = 0, i.e..are homeomorphisms.(H4) we assume that there existsβ> 0, such thatsatisfies thefollowing estimates:Lemma 1.1. Let F : Y×∧→Z be a Cl mapping from a Banach space Y×∧into some Banach space Z. Assume there exists a Junction y|<sub>0 :∧→Y such that Fy (y|-(μ),μ) are homeomorphisms for all |μ|<δ2, and there exist some constantsκ=κ(μ) > 0,σ=σ(μ) > 0, such that for |y-y|-0(μ)|≤δ1,|μ|≤δ2 we havethen for any |μ| <δ2, F(·,μ) has a unique Cr - smooth zero y|- = y|-(μ) near y|<sub>0(μ), and the following estimates hold for |yi-y|<sub>0(μ)|≤δ1, i = 1,2:Next we consider the operator:andFor the operator F, the following conclusion holds.Theorem 1.3. Assume (H1) - (H4). Then there exists constantε3,δ> 0, such that for0 <ε<ε3, for anyλ|∈(λ0-(ε),λ0+(ε)), the function F has a unique zero (x|-z(ε),λ|-(ε)) in aδneighborhood . This orbit satisfies the following estimates:Remark 1.1. Define ,let it is the homoclinic orbitφ(·,λ|-(ε),ε). y(t) are the solution of equation (2.1), and the interplation of {yn}. We hope that y(t) is the homoclinic orbit of equation (2.1), but to date, we unable to complete this proof We hope to carry on this study in our future work.
Keywords/Search Tags:Dynamical system, one-step methods, homoclinic orbit, transversality
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